6x^2-140x-96=0

Solution for 6x^2-140x-96=0 equation:

6x^2-140x-96=0

a = 6; b = -140; c = -96;
Δ = b2-4ac
Δ = -1402-4·6·(-96)
Δ = 21904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21904}=148$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-140)-148}{2*6}=\frac{-8}{12}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-140)+148}{2*6}=\frac{288}{12}
=24
$